Enterprise AI agents are starting to enter customer operations through tools like Adobe’s CX Enterprise, which brings automation, personalization, and agents into corporate workflows. The next step is live conversation. Many agents still sit inside dashboards, tickets, and text prompts, while real customer interaction often happens through voice, video, onboarding calls, live support, and sales meetings. @dTelecom helps builders bring voice, video, STT, TTS, and translation into products where people and AI agents can speak, listen, and respond in real time.

🚨 SlowMist TI Alert 🚨 MistEye has monitored threat intelligence regarding a sophisticated supply chain campaign targeting official Checkmarx distribution channels. The attack involved maliciously overwriting tags in the checkmarx/kics Docker Hub repository and injecting remote payload execution logic into specific extension versions, including checkmarx/cx-dev-assist (1.17.0, 1.19.0) and checkmarx/ast-results (2.63.0, 2.66.0). This campaign specifically aims to exfiltrate developer and cloud credentials to obtain GitHub and npm tokens for lateral propagation. Consequently, this propagation has led to the compromise of the @bitwarden/cli@2026.4.0 package, which now contains a malicious file named bw1.js. These IOCs have been synchronized with clients immediately. It is advised to avoid unverified checkmarx/kics Docker images and strictly refrain from using the compromised extension or CLI versions mentioned above. Immediate auditing of development environments and rotation of any potentially exposed credentials or tokens is strongly recommended. As always, stay vigilant!

Proof: [Lemma] sum(i=1..x) [degree n-1 polynomial] = [degree n polynomial] Proof of lemma: * Notice that x^n - (x-1)^n = x^n - x^n + nx^(n-1) - ... +- 1 = [degree n-1 polynomial, call it C(x)] * Hence by telescoping sums, sum(i=1..x) C(i) = x^n * Given any specific degree n-1 polynomial D(x), re-express it as D(x) = some k * C(x) + [deg <= n-2 stuff]. By induction on n, and by linearity, sum(1..x)D(i) = k * x^n + [deg <= n-1 stuff]. Therefore, sum(i=1...x) i^3 is degree 4, and (sum(i=1...x) i)^2 is degree 2*2 = 4. Now, explicitly evaluate (sum(i=1...x) i)^2 and sum(i=1...x) i^3 on x=1...5, answers are: 1, 9, 36, 100, 225 in both cases The two deg-4 polynomials are the same on five points, therefore they are equal Therefore sqrt(sum(i=1...x) i^3) = sum(i=1...x)